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The string on the violin with the highest pitch is the note E, which has a frequency of 329.6 Hz and a wavelength of 1.032 m. If the string has a mass of 180.0 g and a length of 32.0 cm and is currently producing a wave of frequency 328.1 Hz, how much do you need to change the tension in the
string to produce the note E? Assume string length, string mass, and wavelength remain unchanged in the tuning process.
The back of the book says 1.35 N and i keep getting around 591 N
1. Solve for tension in string
v = 328.1*1.032
v = 338.5992 m/s
Linear Density (u) = 0.18/0.32
Linear Density (u) = 0.5625 kg/m
338.5992= sqrt(Ft/0.5625)
338.5992^2 = Ft/0.5625
114649.418*0.5625 = Ft
64490.297 = Ft
2. Solve for tension required for note E
v = 329.6 *1.032
v = 340.1472 m/s
Linear Density (u) = 0.18/0.32
Linear Density (u) = 0.5625 kg/m
340.1472= sqrt(Ft/0.5625)
340.1472^2 = Ft/0.5625
115700.117*0.5625 = Ft
65081.316= Ft
3. Find the difference in tension
Ft = 65081.316 - 64490.297
Ft = 591.019
string to produce the note E? Assume string length, string mass, and wavelength remain unchanged in the tuning process.
The back of the book says 1.35 N and i keep getting around 591 N
1. Solve for tension in string
v = 328.1*1.032
v = 338.5992 m/s
Linear Density (u) = 0.18/0.32
Linear Density (u) = 0.5625 kg/m
338.5992= sqrt(Ft/0.5625)
338.5992^2 = Ft/0.5625
114649.418*0.5625 = Ft
64490.297 = Ft
2. Solve for tension required for note E
v = 329.6 *1.032
v = 340.1472 m/s
Linear Density (u) = 0.18/0.32
Linear Density (u) = 0.5625 kg/m
340.1472= sqrt(Ft/0.5625)
340.1472^2 = Ft/0.5625
115700.117*0.5625 = Ft
65081.316= Ft
3. Find the difference in tension
Ft = 65081.316 - 64490.297
Ft = 591.019
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