Linear Algebra (Parametric Form)

In summary, the conversation discusses finding the point of intersection between two non-parallel lines in three dimensions, with given equations and values for the variables c and d. The conversation also mentions the use of determinants and a related question from a forum.
  • #1
tweety24
12
0

Homework Statement



L1 : x = (0, 1, 2) + s(1, 0, 2)
L2 : x = (4, 2, c) + t(−2, 0, d)

If c = 5 & d = 0, find the point P on L1 and Q on L2 so that the distance between P & Q is the smallest possible.


Homework Equations



the point of intersection?


The Attempt at a Solution



well the lines aren't parallel or identical in this case so they must intersect at some point.
 
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  • #2
You are thinking about two dimensions. In three dimensions non parallel lines don't have to intersect.
 
  • #3
oh okayy...so then to start off would i need to find the determinant?
 
  • #5
lol yeahh i am
 

Related to Linear Algebra (Parametric Form)

1. What is parametric form in linear algebra?

Parametric form in linear algebra is a way of representing a linear equation using parameters or variables. It is typically written as a system of equations, with each equation representing a different variable. This form is useful for solving systems of equations and graphing linear equations.

2. How is parametric form different from standard form in linear algebra?

The main difference between parametric form and standard form in linear algebra is the way the equations are written. Standard form, also known as slope-intercept form, is written as y = mx + b, where m is the slope and b is the y-intercept. Parametric form, on the other hand, is written as a system of equations with variables and parameters, such as x = at + b and y = ct + d.

3. What are the benefits of using parametric form in linear algebra?

Parametric form allows for a more general representation of linear equations, making it easier to solve systems of equations and graph linear equations. It also allows for more flexibility in representing lines, as it can account for horizontal and vertical lines which cannot be represented in standard form.

4. How do you convert a linear equation from standard form to parametric form?

To convert a linear equation from standard form to parametric form, you can use the following steps:

1. Rewrite the equation in slope-intercept form: y = mx + b

2. Replace the y with a parameter t: y = mt + b

3. Solve for x: x = (1/m)t + b/m

4. Rewrite the equation using t as a parameter: x = at + b, where a = 1/m and b = b/m

5. Can parametric form be used for non-linear equations?

No, parametric form is only applicable for linear equations. Non-linear equations have a different form and require different methods for solving and graphing.

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