- #1
xiaochobitz
- 6
- 0
Homework Statement
Homework Equations
[tex]
\lim(\frac{(x^2)-2x-3}{(x^2)+5x+6})[/tex]
[tex]
x->(-2)
[/tex]
The Attempt at a Solution
anyone can help out on this one?
xiaochobitz said:tends to infinity?
xiaochobitz said:so there is a problem in the question? haha~
whitay said:L'Hopitals?
( 2x - 2 ) / ( 2x + 5 ) -> -2 is -6
Just realized L'Hop won't work cause it isn't 0/0. Sorry.
or
if i divide through by the highest power I get -5/12.
I don't have anything to graph with, but plot it and see.
A limit for a quadratic equation is the value that a function approaches as its independent variable (usually denoted as x) gets closer and closer to a certain value. It represents the behavior of the function at that particular point.
To find the limit of a quadratic equation, you can either use algebraic manipulation or graphing. Algebraically, you can substitute the value the function is approaching into the equation and solve for the limit. Graphically, you can plot the function and observe the behavior of the curve as the independent variable approaches the desired value.
Finding the limit of a quadratic equation can help determine the behavior of the function at a certain point. It can also be used to find the maximum or minimum value of the function, as the limit at that point represents the highest or lowest point on the curve.
The degree of a quadratic equation does not affect its limit. As the independent variable approaches a certain value, the function will still approach a fixed value. However, the degree can affect the speed at which the function approaches the limit, which can be observed by graphing the function.
Yes, there are restrictions when finding the limit of a quadratic equation. The function must be continuous at the point where the limit is being evaluated. This means that the function must have a defined value at that point and the left and right limits must be equal. If this condition is not met, the limit does not exist.