pivoxa15 said:Take n/(n+1)-n/(n+2) as n->infinity results in the limit 0
But take the same equation convert it to n/(n+1)/(n+2) as n-> infinity results in the limit 1.
?? And if you were to "convert" it into something else it is not equal to you would get yet a different answer! Garbage in, garbage out.pivoxa15 said:Take n/(n+1)-n/(n+2) as n->infinity results in the limit 0
But take the same equation convert it to n/(n+1)/(n+2) as n-> infinity results in the limit 1.
What is going on? The expression is the same yet you get two different limits. Something is wrong.
HallsofIvy said:?? And if you were to "convert" it into something else it is not equal to you would get yet a different answer! Garbage in, garbage out.
The limit of n/(n+1)-n/(n+2) as n->Infinity is 0.
To find the limit of a function as n approaches Infinity, you can plug in larger and larger values for n and see if the function approaches a specific value. Alternatively, you can use algebraic techniques such as factoring or rationalizing the denominator to simplify the function and determine the limit.
Yes, the limit of a function as n->Infinity can be a negative number. It depends on the behavior of the function as n gets larger and larger.
If the limit of a function as n->Infinity is undefined, it means that the function either approaches infinity or negative infinity as n gets larger and larger. This can also occur if there is a vertical asymptote in the function.
Yes, the limit of a function as n->Infinity can be a fraction. It depends on the behavior of the function as n gets larger and larger.