L'Hopital's rule for increasing functions

In summary, L'Hopital's rule is a powerful tool in evaluating limits of indeterminate forms, especially those with polynomial terms. It works by taking the derivative of polynomials, which reduces the exponent until it becomes a constant function and the limit can be evaluated. This rule can also be applied to more complex functions, but different techniques such as Taylor series expansion or using norms and bounds may be needed to handle them. By transforming the expression into something more manageable, it becomes possible to evaluate the limit and solve the problem.
  • #1
fakecop
42
0
L'Hopital's rule greatly simplifies the evaluation of limits of indeterminate forms, especially those with polynomial terms. This is because every time you take the derivative of a polynomial, the exponent decreases by 1, until it becomes a constant function, at which point the limit can be evaluated.

So the question is, how can you apply L'Hopital's rule to an indeterminate form such as e^x/x^x? or x^x/x!? for some functions, such as the double exponential, factorial, and hyperoperations (tetration, pentation...) each successive ordered derivative increases everytime you differentiate.

So is there a way to resolve this problem using the tools of elementary calculus? I know that for series there are tests to test convergence, but is there a similar procedure for continuous functions?
 
Last edited:
Physics news on Phys.org
  • #2
What we are trying to do with L'Hopital's rule is not reduce the degree of the polynomial though that happens sometimes, we are trying to reduce the limit so that it is not an indeterminate form.

Here is a humorous example
$$\lim_{x \rightarrow 0} \frac{\sinh \, \tanh \, x-\tanh \, \sinh \, x}{\tan \, \sin \, x-\sin \, \tan \, x}=1$$

a more manageable example is
$$\lim_{x \rightarrow 0} \frac{\tan \, x}{\sin \, x}=1$$
 
  • #3
Hey fakecop.

There are different ways to look at problems like this.

One way that pops up (for your problem) is to do a taylor series expansion of e^x and then divide each term by x^x.

This means that if you have a term a_n*x^n / x^x, then you will have a_n * x^(n-x).

If you then take the limit of each term (since x > n as x -> infinity) then you can show that each term goes to 0 and thus the limit goes to 0 as well.

Other techniques include using norms and bounds to show that a limit is bounded by some expression (possibly with an error term) attached. This idea is used in things like Euler-Mclaurin formula where you want to get a relationship between sums and integrals and is used when integrating the integral is easy, but the sum is not (in terms of an analytic evaluation).

In short, you basically think of ways to take the expression and transform it into something else that is exact or a good enough approximation, and use these facts to see if you can use that expression or transform it into something else that is manageable (and so on) by going from one decomposition to another.
 

Related to L'Hopital's rule for increasing functions

1. What is L'Hopital's rule for increasing functions?

L'Hopital's rule is a mathematical theorem that allows us to evaluate the limit of a quotient of two functions, where both the numerator and denominator approach zero or infinity, by taking the derivative of both functions and then evaluating the limit again.

2. When can L'Hopital's rule be applied?

L'Hopital's rule can only be applied when the limit of the original quotient is in an indeterminate form, such as 0/0 or ∞/∞. Additionally, both the numerator and denominator must be continuous and differentiable in the given interval.

3. How do you use L'Hopital's rule for increasing functions?

To use L'Hopital's rule for increasing functions, we first take the derivative of both the numerator and denominator of the original quotient. Then, we evaluate the limit of the new quotient. If this limit still results in an indeterminate form, we can repeat the process until we reach a definite value or determine that the limit does not exist.

4. What is the significance of L'Hopital's rule for increasing functions?

L'Hopital's rule is significant because it provides us with a method to evaluate limits that would otherwise be difficult or impossible to solve. It is particularly useful for evaluating limits involving trigonometric, exponential, and logarithmic functions.

5. Are there any limitations to using L'Hopital's rule for increasing functions?

Yes, L'Hopital's rule cannot be used to evaluate limits where the numerator and denominator approach zero or infinity at different rates, or when the functions are not continuous or differentiable in the given interval. It also cannot be used to evaluate limits involving products, powers, or sums of functions.

Similar threads

  • Calculus
Replies
9
Views
2K
Replies
10
Views
1K
  • Science and Math Textbooks
Replies
3
Views
955
Replies
1
Views
2K
  • Calculus and Beyond Homework Help
Replies
17
Views
1K
  • Calculus
Replies
17
Views
1K
Replies
2
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
2K
Replies
3
Views
5K
Back
Top