Apologies, I had to do it really quickly. Is the answer correct though ?BvU said:Check your units
Where have I gone wrong ?BvU said:No
Latent heat is the amount of energy required to change the state of a substance without changing its temperature. In the case of ice melting, the latent heat is the amount of energy needed to change the solid ice into liquid water without changing its temperature.
Latent heat is typically measured in units of joules (J) or calories (cal). In the context of the given scenario, it is measured in kilowatts (kW) since the oven is providing 1kW of energy to melt the ice.
The specific latent heat of fusion for ice is the amount of energy required to melt one gram of ice at 0°C into liquid water at the same temperature. It is approximately 334 J/g, or 79.7 cal/g.
The amount of ice affects the latent heat required as it is directly proportional. This means that the more ice there is, the more energy is needed to melt it. In the given scenario, since there is 50g of ice, it will require 50 times the specific latent heat of fusion to melt.
The oven's power directly affects the rate of energy transfer to the ice. The higher the power, the faster the ice will melt. In the given scenario, with a 1kW oven, the ice will melt faster compared to a lower powered oven. However, the total amount of energy required to melt the ice will remain the same regardless of the oven's power.