Laplace transform of (e^-s) / [ (s)(s-3) ]

In summary, the conversation discusses the process of finding the Laplace transform of (e^-s) / [ (s)(s-3) ] and the difference between Laplace and inverse Laplace transforms. The author's ans does not include H(t-a), but it is unclear if this is incorrect or if the problem was asking for the inverse Laplace transform.
  • #1
foo9008
678
4

Homework Statement



find the laplace transform of (e^-s) / [ (s)(s-3) ]

since there's (e^-s) which can be found in L { f(t-a) H(t-a) } = (e^-(as)) F(s) , so , i found a = 1 , then i found F(s) = 1/ [ (s)(s-3) ] , formula :
HGbjXV9.jpg


i have attached the working below , is it correct ? btw , the author's ans doesn't have H(t-a) , is the author's ans wrong ?
author's ans :

2v2kPyD.jpg


Homework Equations

The Attempt at a Solution


my working :
AD0HQrk.png


which is correct ? the author ? or me ?
 
Last edited:
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  • #2
foo9008 said:

Homework Statement



find the laplace transform of (e^-s) / [ (s)(s-3) ]

since there's (e^-s) which can be found in L { f(t-a) H(t-a) } = (e^-(as)) F(s) , so , i found a = 1 , then i found F(s) = 1/ [ (s)(s-3) ] , formula :
HGbjXV9.jpg


i have attached the working below , is it correct ? btw , the author's ans doesn't have H(t-a) , is the author's ans wrong ?
author's ans :

2v2kPyD.jpg


Homework Equations

The Attempt at a Solution


my working :
AD0HQrk.png


which is correct ? the author ? or me ?

There is no way that an author would have asked you to find the Laplace transform of ##e^{-s}/(s(s-3))##. Are you sure it does not ask for the INVERSE Laplace transform? There is a huge difference between these two concepts.
 

Related to Laplace transform of (e^-s) / [ (s)(s-3) ]

What is the Laplace transform of (e^-s) / [ (s)(s-3) ]?

The Laplace transform of (e^-s) / [ (s)(s-3) ] is 1 / (s+1)(s-3).

What is the significance of the Laplace transform of (e^-s) / [ (s)(s-3) ]?

The Laplace transform allows for the transformation of a function from the time domain to the frequency domain, making it easier to solve differential equations.

How is the Laplace transform of (e^-s) / [ (s)(s-3) ] calculated?

The Laplace transform of a function f(t) is given by the integral of e^(-st)f(t) from 0 to infinity. In this case, the integral would be 1/(s+1)(s-3).

What is the inverse Laplace transform of 1 / (s+1)(s-3)?

The inverse Laplace transform of 1 / (s+1)(s-3) is (e^3 - e^(-t)) / 4.

What are some applications of the Laplace transform of (e^-s) / [ (s)(s-3) ]?

The Laplace transform is commonly used in engineering and physics to analyze systems and solve differential equations. It also has applications in signal processing and control theory.

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