Isomorphism between G and Z x Z_2 if G has a normal subgroup isomorphic to Z_2

In summary, the conversation discusses a problem involving a group G and its normal subgroup H, and the relationship between their quotient groups. The conversation also mentions the concept of a direct product and its special properties, such as the factors commuting with each other. The problem is ultimately solved by considering the abelianity of G.
  • #1
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Homework Statement


If G contains a normal subgroup H which is isomorphic to [tex]\mathbb{Z}_2[/tex], and if the corresponding quotient group is infinite cyclic, prove that G is isomorphic to [tex]\mathbb{Z}\times\mathbb{Z}_2[/tex]

The Attempt at a Solution


[tex]G/H[/tex] is infinite cyclic, this means that any [tex]g\{h1,h2\}[/tex] is generated by some [tex]\gamma\{h1,h2\}[/tex] with [tex]\gamma\in G[/tex]. [tex]\gamma=g^n[/tex] because H is normal. But now?
 
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  • #2
Do you know any general property of a group [tex]G[/tex] such that, when [tex]G[/tex] has this property and [tex]N[/tex] is a normal subgroup of [tex]G[/tex], you can conclude that [tex]G \cong N \times G/N[/tex]?

(Hint: in the direct product [tex]H \times K[/tex] of two groups, what is the relationship between the subgroups [tex]H \times 1[/tex] and [tex]1 \times K[/tex]?)
 
  • #3
ystael said:
Do you know any general property of a group [tex]G[/tex] such that, when [tex]G[/tex] has this property and [tex]N[/tex] is a normal subgroup of [tex]G[/tex], you can conclude that [tex]G \cong N \times G/N[/tex]?

(Hint: in the direct product [tex]H \times K[/tex] of two groups, what is the relationship between the subgroups [tex]H \times 1[/tex] and [tex]1 \times K[/tex]?)

I do not know any general property of this kind... the subgroups H x 1 and 1 x K only have the identity in common and (H x 1)(1 x K)=H x K, but I do not see how this helps...
 
  • #4
The "general property of [tex]G[/tex]" I was referring to is "[tex]G[/tex] is abelian". One way to understand the thing that makes direct products special is that the factors commute with each other: in the product above, [tex](h, 1)(1, k) = (1, k)(h, 1) = (h, k)[/tex].

In your original problem, what happens if [tex]G[/tex] is abelian? What happens if it's not?
 
  • #5
I really do not understand... what is the use of the fact that the factors of the direct products commute with each other?
 

Related to Isomorphism between G and Z x Z_2 if G has a normal subgroup isomorphic to Z_2

1. What is an isomorphism?

An isomorphism is a mathematical concept that describes a one-to-one correspondence between two mathematical structures that preserves their operations and structures.

2. What is the significance of a normal subgroup in this context?

A normal subgroup is a subgroup of a group that is closed under the group's operation and is also invariant under conjugation by elements of the group. In this context, it means that the subgroup is "compatible" with the larger group and can be used to construct an isomorphism between the two.

3. How is the isomorphism between G and Z x Z_2 constructed?

The isomorphism is constructed by mapping each element of G to a pair of elements, one from Z and one from Z_2, in a way that preserves the group operation. This mapping is possible because of the normal subgroup isomorphic to Z_2.

4. Can there be multiple isomorphisms between G and Z x Z_2?

Yes, there can be multiple isomorphisms between two groups. In this case, there may be different ways to map the elements of G to elements of Z x Z_2 while preserving the group operation. However, all of these isomorphisms will be equivalent in the sense that they will have the same underlying structure.

5. How is the isomorphism between G and Z x Z_2 useful in mathematics?

The isomorphism between G and Z x Z_2 can be useful in solving problems and proving theorems in group theory. It allows us to understand the structure and properties of G by relating it to the more familiar group Z x Z_2. It also helps in constructing new groups by using the isomorphism to map elements between different groups.

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