- #1
chaotixmonjuish
- 287
- 0
n=p1r1...pkrk
In order for p to be a perfect square, r must be even. Therefore
n=p12h1...pk2hk
taking the square root of both sides I'm just left with
n=p1h1...pkhk
Does this work as a proof that n is a perfect square if r is even? It's a homework problem and I'm not sure if this is sufficient or correct at all.
In order for p to be a perfect square, r must be even. Therefore
n=p12h1...pk2hk
taking the square root of both sides I'm just left with
n=p1h1...pkhk
Does this work as a proof that n is a perfect square if r is even? It's a homework problem and I'm not sure if this is sufficient or correct at all.