- #1
mhill
- 189
- 1
although is not valid in general (since an Euler product usually converges only when Re(s) >1)
[tex] \frac{ d \zeta(1/2)}{\zeta (1/2)}= -\sum_{p} log(p)(1-p^{1/2} [/tex]
[tex] \frac{ d \zeta(1/2)}{\zeta (1/2)}= -\sum_{p} log(p)(1-p^{1/2} [/tex]