novop said:Never go full retard...
The equation is discontinuous when the denominator is zero.
Continuity is a property of a function where there are no sudden jumps or breaks in the graph. This means that the function can be drawn without lifting your pencil from the paper.
A function is continuous if its graph is a continuous line with no gaps or breaks. It must also have the same value at each point on the graph, meaning that the limit of the function at that point must exist and equal the function's value.
Yes, the equation f(x)=(x^2-1)/(x+1) is continuous. This can be determined by checking that there are no breaks or gaps in the graph, and by taking the limit of the function at each point and verifying that it equals the function's value at that point.
This is a subjective question and cannot be answered definitively. However, some may consider this question to be "stupid" because it is asking about a basic concept in calculus and the answer can easily be found by researching or studying continuity.
Yes, a function can be continuous at some points but not others. This is known as point discontinuity. For example, the function f(x) = 1/x is continuous at all points except x = 0, where it has a vertical asymptote and is therefore not continuous.