Intro physics question involving magnitudes and vectors

[Kevin Bertham]

You’re hanging from a chinning bar, with your ;arms at right angles to each other. The magnitudes of the forces exerted by both your arms are the same, and together they exert just enough upward force to support your weight, 620 N. (a) Sketch the two force vectors for your arms, along with their
resultant, and (b) use components to find the magnitude of each of the two “arm” force vectors.

So i drew the triangles out with 310 across the x-axis and 620 down.

The 90 degree angle as well as the two 45`s . I went to find the H which is cos 45= O/H , multiply by H on both sides so its H*cos45= 310 divide both by cos 45 which leaves you with H=310/cos45 which leaves with 438 N as the resultant. That is what i did anyway I don't think i am correct but if someone could give this a peak.

 

[BvU]

Want a second opinion ? You're still correct !

 

[Kevin Bertham]

lol they said i needed to follow the posting guidelines

 

[BvU]

Still true: use the template (you should also READ the guidelines ;-) )

 

[HalfLostAndSearching]

Your approach is correct. The magnitude of each arm force vector can be found using the Pythagorean theorem:
a^2 + b^2 = c^2
where a and b are the horizontal and vertical components of the force vector, and c is the magnitude.
In this case, a = 310 N and b = 620 N.
So, c = √(310^2 + 620^2) = 438 N.
Therefore, the magnitude of each arm force vector is 438 N.
Your sketch should show the two arm force vectors, each with a magnitude of 438 N, and the resultant force vector, pointing upwards, with a magnitude of 620 N.
Great job!