Integration by Parts to find integral

In summary, integration by parts is a mathematical technique used to find the integral of a function by breaking it down into simpler parts. It is typically used when the integral involves a product of two functions, and one of the functions becomes simpler when differentiated. To apply integration by parts, one must use the formula: ∫ u dv = uv - ∫ v du, where u and v are functions and dv and du are the derivatives of those functions. The steps for using integration by parts are: 1. Identify u and dv in the integral. 2. Find the derivative of u and the antiderivative of dv. 3. Substitute these into the integration by parts formula. 4. Simplify and solve for the integral
  • #1
cummings15
17
0

Homework Statement



find the integral of cot^(-1)of (5x)


Homework Equations



Integration by parts

The Attempt at a Solution



u = x
du = dx
dv = cot ^ (-1)
v = ?

and then i would plug into equation [uv- integral of vdu ]
 
Physics news on Phys.org
  • #2
∫cot-1(5x)dx

It would be more benefical to have u=cot-1(5x) and dv=dx.
 

Related to Integration by Parts to find integral

What is integration by parts?

Integration by parts is a mathematical technique used to find the integral of a function by breaking it down into simpler parts.

When should I use integration by parts?

Integration by parts is typically used when the integral involves a product of two functions, and one of the functions becomes simpler when differentiated.

How do I apply integration by parts?

To apply integration by parts, you must use the formula: ∫ u dv = uv - ∫ v du, where u and v are functions and dv and du are the derivatives of those functions.

What are the steps for using integration by parts?

The steps for using integration by parts are:
1. Identify u and dv in the integral.
2. Find the derivative of u and the antiderivative of dv.
3. Substitute these into the integration by parts formula.
4. Simplify and solve for the integral.

Can integration by parts be used for definite integrals?

Yes, integration by parts can be used for definite integrals by applying the formula and then substituting the limits of integration into the final solution.

Similar threads

  • Calculus and Beyond Homework Help
Replies
1
Views
927
  • Calculus and Beyond Homework Help
Replies
22
Views
1K
  • Calculus and Beyond Homework Help
Replies
10
Views
539
  • Calculus and Beyond Homework Help
Replies
3
Views
1K
  • Calculus and Beyond Homework Help
Replies
3
Views
3K
  • Calculus and Beyond Homework Help
Replies
15
Views
812
  • Calculus and Beyond Homework Help
Replies
19
Views
827
  • Calculus and Beyond Homework Help
Replies
4
Views
665
Replies
2
Views
1K
  • Calculus and Beyond Homework Help
Replies
1
Views
789
Back
Top