- #1
cathy
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Homework Statement
(2x^3-2x+1)/(x^2/3x)
Find the integral.
2. The attempt at a solution
So I've been on this problem for like an hour now and I don't know what I'm doing wrong. So I used long division and got
2x+ (4x+1)/(x^2-3x)
∫2x + ∫(4x+1)/(x^2-3x)
= x^2 + ∫(4x+1)/(x^2-3x).
For that next part, I used partial fractions.
A/x + B/(x-3) = 4x+1
Solved for a= -1/3
Solved for b= 13/3
Put everything together and solving for that integral, I got
x^2- 1/3ln(x) + 13/3ln(x-3)
and it's wrong.
Where am I going wrong? I'm so confused.
Thank for any help in advance.