- #1
Zeth
- 23
- 0
[tex]\int_{-2} ^2 \frac{dx}{4+x^2}[/tex]
I use the trig substitution and get everything done but for some reason I can't get the answer, here's all my working:
[tex] x = 2 \tan\theta[/tex]
[tex] dx = 2 \sec^2\theta[/tex]
[tex]4+x^2=4(1+\tan\theta)=4\sec^2\theta[/tex]
[tex]\int \frac{2\sec^2\theta d\theta}{4\sec^2\theta}[/tex]
[tex]\int \frac{1}{2\sec^2\theta}d\theta[/tex]
[tex]\int 2\cos^2\theta d\theta[/tex]
[tex]\int (1+\cos2\theta)[/tex]
[tex]\theta + \frac{\sin2\theta}{2}[/tex]
[tex][\arctan\frac{x}{2} + \frac{\sin 2 \arctan \frac{x}{2}}{2}]_{-2} ^2[/tex]
which is nothing close to what am I meant to get [tex]\frac{\pi}{4}
I use the trig substitution and get everything done but for some reason I can't get the answer, here's all my working:
[tex] x = 2 \tan\theta[/tex]
[tex] dx = 2 \sec^2\theta[/tex]
[tex]4+x^2=4(1+\tan\theta)=4\sec^2\theta[/tex]
[tex]\int \frac{2\sec^2\theta d\theta}{4\sec^2\theta}[/tex]
[tex]\int \frac{1}{2\sec^2\theta}d\theta[/tex]
[tex]\int 2\cos^2\theta d\theta[/tex]
[tex]\int (1+\cos2\theta)[/tex]
[tex]\theta + \frac{\sin2\theta}{2}[/tex]
[tex][\arctan\frac{x}{2} + \frac{\sin 2 \arctan \frac{x}{2}}{2}]_{-2} ^2[/tex]
which is nothing close to what am I meant to get [tex]\frac{\pi}{4}