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- #1

kxy \frac{dy}{dx} = y^2 - x^2 \quad , \quad

y(1) = 0

$

My professor suggests substituting P in for y^2, such that:

$

P = y^2

dP = 2y dy

$

I am proceeding with an integrating factor method, but unable to use it to separate the variables, may be coming up with the wrong integrating factor ( x )