- #1
coolhand
- 15
- 0
Hey everyone, I'm a long-time visitor, it's my first time posting though.
I have a homework problem that is causing me considerable consternation:
(y^3)*(dy/dx)=(8y^4+14)*cos(x); y(0)=C
Oh, and we're supposed to solve the initial-value problem, and then solve for the particular solution in the form (y^4)=...
I first used separation of variables and then integrated to get:
(y^4) = (1/4)*Ce^(32sin(x))-(7/4)
Now that I've solved for the general initial-value equation, I don't know where to go from here. The only way I could think to solve for C is to plug in 0 for x, and C for y--giving you:
(C^4)=(1/4)*C*(e^0)-(7/4)
C=((1/4)-(7/4))^(1/3)
As this is a non-real answer, I cannot figure out where I went wrong. Also, I was told that we would not need to use complex numbers for any of these homework problems.
I have a homework problem that is causing me considerable consternation:
(y^3)*(dy/dx)=(8y^4+14)*cos(x); y(0)=C
Oh, and we're supposed to solve the initial-value problem, and then solve for the particular solution in the form (y^4)=...
I first used separation of variables and then integrated to get:
(y^4) = (1/4)*Ce^(32sin(x))-(7/4)
Now that I've solved for the general initial-value equation, I don't know where to go from here. The only way I could think to solve for C is to plug in 0 for x, and C for y--giving you:
(C^4)=(1/4)*C*(e^0)-(7/4)
C=((1/4)-(7/4))^(1/3)
As this is a non-real answer, I cannot figure out where I went wrong. Also, I was told that we would not need to use complex numbers for any of these homework problems.