Impulse and Momentum of an object

[89kyle]

Homework Statement

Question 2: A one-dimensional impulse force acts on a 3.0-kg object, as described by the graph below. Find
(a) the magnitude of the impulse given to the object,
(b) the magnitude of the average force, and
(c) the final speed if the object had an initial speed of 6.0 m/s.

Homework Equations

impulse=mv-initialmv

The Attempt at a Solution

 

[matt_crouch]

have you attempted the solution? how far have you got where are you stuck?
you need to put the graph up as well i think =]

 

[kerimek]

(a) The impulse given to the object can be found by calculating the area under the graph. In this case, the impulse is equal to the change in momentum, which can be calculated by multiplying the mass of the object (3.0 kg) by the change in velocity. From the graph, we can see that the change in velocity is 4.0 m/s, therefore the impulse is 3.0 kg * 4.0 m/s = 12 Ns.

(b) The average force can be calculated by dividing the impulse by the time interval over which it acts. From the graph, we can see that the time interval is 2 seconds. Therefore, the average force is 12 Ns / 2 s = 6 N.

(c) To find the final speed of the object, we can use the equation v = u + at, where v is the final speed, u is the initial speed, a is the acceleration, and t is the time interval. We know that the initial speed is 6.0 m/s and the time interval is 2 seconds. From the graph, we can see that the acceleration is 2 m/s^2. Therefore, the final speed is calculated as v = 6.0 m/s + (2 m/s^2 * 2 s) = 10 m/s.