- #1
fluppocinonys
- 19
- 1
Two glass bulbs of equal volume are joined by a narrow tube and are filled with gas at s.t.p. (standard temperature and pressure where [tex]\theta = {0^ \circ }{\rm{C}}[/tex] and [tex]p = 1.01 \times {10^5}[/tex] Pa). When one bulb is kept in melting ice and the other is placed in hot bath, the new pressure is 1.166 x 105 Pa. Calculate the temperature of the bath.
I tried to use
[tex]\begin{array}{l}
\frac{{{p_1}{v_1}}}{{{T_1}}} = \frac{{{p_2}{v_2}}}{{{T_2}}} \\
{v_1} = {v_2} \\
\frac{{{p_1}}}{{{T_1}}} = \frac{{{p_2}}}{{{T_2}}} \\
\end{array}[/tex]
but failed to arrive at the answer. The answer is 370K
Can anyone guide me? Thanks.
I tried to use
[tex]\begin{array}{l}
\frac{{{p_1}{v_1}}}{{{T_1}}} = \frac{{{p_2}{v_2}}}{{{T_2}}} \\
{v_1} = {v_2} \\
\frac{{{p_1}}}{{{T_1}}} = \frac{{{p_2}}}{{{T_2}}} \\
\end{array}[/tex]
but failed to arrive at the answer. The answer is 370K
Can anyone guide me? Thanks.