- Thread starter
- #1

#### karush

##### Well-known member

- Jan 31, 2012

- 2,725

View attachment 1202

(a) $E\cup H = 88-39=49$ and since $32+28=60$ then $b=60-49= E\cap H = 11$

so $a=32-11=21$ and $c=28-11=17$

hope this ok before (b) and (c)

(a) $E\cup H = 88-39=49$ and since $32+28=60$ then $b=60-49= E\cap H = 11$

so $a=32-11=21$ and $c=28-11=17$

hope this ok before (b) and (c)

Last edited: