- #1
Jonny_trigonometry
- 452
- 0
I was wondering how to solve this integral:
[tex]\int_{0}^{1}\sqrt{t^2-1}\,dt[/tex]
When I punch it into mathematica, it gives:
[tex] 1/2 t\sqrt{-1+t^2}-1/2\log{(t+\sqrt{-1+t^2})} [/tex]
I was wondering what steps are done to get this result
I suppose I forgot to enter it in as a definate integral, but still...
[tex]\int_{0}^{1}\sqrt{t^2-1}\,dt[/tex]
When I punch it into mathematica, it gives:
[tex] 1/2 t\sqrt{-1+t^2}-1/2\log{(t+\sqrt{-1+t^2})} [/tex]
I was wondering what steps are done to get this result
I suppose I forgot to enter it in as a definate integral, but still...
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