How to Solve Exponential Equations?

  • MHB
  • Thread starter Alexeia
  • Start date
  • Tags
    Exponential
In summary, the conversation discusses solving an equation for $2^x$ in terms of $y$, which involves using the property of exponents. The second question asks for the solutions of the equation when $y$ is the largest possible integer value, which is 3.
  • #1
Alexeia
9
0
Hi,

I attached a pdf with a question and its answers. I don't understand the whole thing basically, e.g what their asking for..

1.2.1;1.2.2;1.2.3

1.2.2 - How many solutions for x will the equation have..?
1.2.3 - Largest integer for which it will have solutions..?

Any explanations will help..

Thanks
 

Attachments

  • Questions_Answers.pdf
    128.1 KB · Views: 56
Mathematics news on Phys.org
  • #2
Here are the questions:

1.2 Given: \(\displaystyle 2^x+2^{x+2}=-5y+20\)

1.2.1 Express \(\displaystyle 2^x\) in terms of $y$.

Here, you are expected to solve the equation for $2^x$. Recall the property of exponents:

\(\displaystyle a^{b+c}=a^ba^c\)

which means:

\(\displaystyle 2^{x+2}=2^x2^2=4\cdot2^x\)

So now the equation becomes:

\(\displaystyle 2^x+4\cdot2^x=-5y+20\)

Can you continue? Combine the two like terms on the left side as your first step.

After we get this part solved, where you understand it, we can move on to the remaining parts, as they depend on this part.
 
  • #3
MarkFL said:
Here are the questions:

1.2 Given: \(\displaystyle 2^x+2^{x+2}=-5y+20\)

1.2.1 Express \(\displaystyle 2^x\) in terms of $y$.

Here, you are expected to solve the equation for $2^x$. Recall the property of exponents:

\(\displaystyle a^{b+c}=a^ba^c\)

which means:

\(\displaystyle 2^{x+2}=2^x2^2=4\cdot2^x\)

So now the equation becomes:

\(\displaystyle 2^x+4\cdot2^x=-5y+20\)

Can you continue? Combine the two like terms on the left side as your first step.

After we get this part solved, where you understand it, we can move on to the remaining parts, as they depend on this part.
Awesome, the way the questioned was asked confused me.. Another way of saying it then is - Solve for 2^x.. But it doesn't yet mean to solve for x right?

Then Question 1.2.3, can you shed some light on that one pls?
 
  • #4
Alexeia said:
Then Question 1.2.3, can you shed some light on that one pls?
1.2 Given:
\[
2^x+2^{x+2}=-5y+20\tag{1}
\]
...
1.2.3: Solve for $x$ if $y$ is the largest possible integer value for which (1) will have solutions.

Question 1.2.3 (admittedly, a bit convoluted) says the following. Let $P(y)$ be some property of $y$ (to be discussed later). Find the largest integer $y$ such that $P(y)$ holds and call it $y_{\text{max}}$. Now solve (1) for $x$ assuming that $y=y_{\text{max}}$.

The property $P(y)$ in question is that (1) has a solution $x$ for a given $y$. Note that the equation
\[
2^x+2^{x+2}=z
\]
has some solution $x$ iff $z>0$. Therefore,
\[
P(y)\text{ holds }\iff -5y+20>0 \iff y<4.
\]
The largest $y_{\text{max}}$ satisfying this property is 3 (since the inequality is strict). Therefore, you are supposed to solve (1) when $y=3$.
 
  • #5
for reaching out. Exponential equations are mathematical equations that involve an unknown variable in the exponent, such as 2^x or e^x. They are commonly used in science and mathematics to model growth and decay processes.

In the attached pdf, the questions are asking about the solutions to a specific exponential equation. In 1.2.2, the question is asking how many different values of x will satisfy the equation. This means that the equation will have multiple solutions, or values of x, that make the equation true. In 1.2.3, the question is asking for the largest integer value of x that will satisfy the equation. This means that the solutions to the equation will be limited to whole numbers, or integers.

To solve these types of equations, you can use algebraic methods such as substitution or logarithms. It's important to carefully read the question and identify what is being asked for in order to find the correct solutions.

I hope this helps to clarify the concepts of exponential equations. Please let me know if you have any further questions. Keep up the good work in your studies!
 

Related to How to Solve Exponential Equations?

1. What is an exponential equation?

An exponential equation is an equation in the form of y = ab^x, where a and b are constants and x is the variable. The variable x is typically the exponent, giving the equation its name.

2. How do you solve an exponential equation?

To solve an exponential equation, you can use either logarithms or algebraic methods. If the equation is in the form of y = ab^x, you can take the logarithm of both sides to isolate the variable x. If the equation is in the form of ab^x = c, you can use algebraic methods to solve for x.

3. What is the difference between an exponential equation and a linear equation?

The main difference between an exponential equation and a linear equation is that the variable in an exponential equation is in the exponent, while the variable in a linear equation is typically in the first power. This means that the graph of an exponential equation will be a curve, while the graph of a linear equation will be a straight line.

4. What are some real-life applications of exponential equations?

Exponential equations are commonly used in finance, biology, and physics. They can be used to model population growth, compound interest, radioactive decay, and many other phenomena.

5. Can an exponential equation have a negative exponent?

Yes, an exponential equation can have a negative exponent. This will result in a fraction with a negative exponent, which can be rewritten as a positive exponent in the denominator. For example, the equation y = 2^(-x) can be rewritten as y = 1/(2^x).

Similar threads

Replies
3
Views
1K
Replies
3
Views
1K
  • General Math
Replies
2
Views
1K
  • Differential Equations
Replies
7
Views
1K
Replies
2
Views
1K
Replies
2
Views
367
Replies
11
Views
830
Replies
4
Views
843
Replies
3
Views
2K
Replies
7
Views
1K
Back
Top