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#### find_the_fun

##### Active member

- Feb 1, 2012

- 166

\(\displaystyle y\ln{x}\frac{dx}{dy}=(\frac{y+1}{x})^2\)

I got it down to

\(\displaystyle \ln{x}x^3-\frac{x^3}{3}=y^3+3y+y^2\)

At this point I had no idea how to solve having y^3 y^2 and y terms so I did what any good student would do and checked the back of the book. The answer given was basically the same as I had got. My question is how do you know when you are done?