Gee, we don't know, either.Pen1460 said:a = 5 / (3s^(1/3) + s^(5/2))
I don't know if I can do partial fractions on this one, or maybe I'm just doing it wrong.
Pen1460 said:a = 5 / (3s^(1/3) + s^(5/2))
I don't know if I can do partial fractions on this one, or maybe I'm just doing it wrong.
Maybe you are doing it wrong. If you had included the complete problem statement, we might have a better idea about where you might have gone astray.Pen1460 said:a = 5 / (3s^(1/3) + s^(5/2))
I don't know if I can do partial fractions on this one, or maybe I'm just doing it wrong.
dirk_mec1 said:Hint: vdv = ads
Integrating to get velocity involves finding the antiderivative of the acceleration function and evaluating it at the limits of the interval. This will give you the displacement function, which can then be differentiated to get the velocity function.
Integration is the process of finding the antiderivative of a function, while differentiation is the process of finding the derivative of a function. In other words, integration deals with finding the original function from its rate of change, while differentiation deals with finding the rate of change from the original function.
Yes, integration can be used to find velocity in any situation where the acceleration is known. However, the process may vary depending on the complexity of the acceleration function and the limits of the interval.
Integrating to get velocity has many applications in physics and engineering, such as calculating the speed of an object in motion, determining the displacement of an object over time, and analyzing the motion of particles in a system.
There are various techniques for integrating to get velocity, such as using integration by parts or substitution. However, there is no shortcut or trick that can be universally applied, and the best approach will depend on the specific function being integrated.