How to find m1 in T = ( m1c1T1 + m2c2T2 ) / ( m1c1 + m2c2 )

If so, you should be able to find a lot of help on the internet. Just Google the term “solving linear equations” or “linear algebraic equations” and you should be presented with a wealth of information.
  • #1
YNesterov
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Homework Statement


How to find mass of one of the two liquids being mixed if we know all other variables in this formula T = ( m1c1T1 + m2c2T2 ) / ( m1c1 + m2c2 ) ?

Homework Equations


T = ( m1c1T1 + m2c2T2 ) / ( m1c1 + m2c2 )

The Attempt at a Solution

 
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  • #2
YNesterov said:

Homework Statement


How to find mass of one of the two liquids being mixed if we know all other variables in this formula T = ( m1c1T1 + m2c2T2 ) / ( m1c1 + m2c2 ) ?

Homework Equations


T = ( m1c1T1 + m2c2T2 ) / ( m1c1 + m2c2 )

The Attempt at a Solution


Hi YNesterov

:welcome:

In order to get help you have to put some efforts first. So, what have you tried so far?

 
  • #3
Are you saying that you don’t know how to solve a linear algebraic equation in one unknown?
 
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Related to How to find m1 in T = ( m1c1T1 + m2c2T2 ) / ( m1c1 + m2c2 )

1. How do I solve for m1 in the equation T = ( m1c1T1 + m2c2T2 ) / ( m1c1 + m2c2 )?

To solve for m1 in this equation, you will need to isolate m1 on one side of the equation. This can be done by first multiplying both sides by the denominator (m1c1 + m2c2) to cancel it out on the right side. Then, you can distribute the T term on the left side to get m1c1T = m1c1T1 + m2c2T2. Finally, you can subtract m1c1T1 from both sides and divide both sides by c1T to get the final equation of m1 = (m2c2T2 - T) / (c1T - c2T2).

2. What do the variables in the equation represent?

The variables in this equation represent the following:

  • T: the final temperature of the system
  • m1: the mass of the first object
  • m2: the mass of the second object
  • c1: the specific heat capacity of the first object
  • c2: the specific heat capacity of the second object
  • T1: the initial temperature of the first object
  • T2: the initial temperature of the second object

3. Can this equation be used for any type of system?

Yes, this equation can be used for any type of system as long as the objects involved have defined masses and specific heat capacities. However, it is important to note that this equation assumes that the system is closed and there is no external heat or energy transfer.

4. What is the significance of this equation in scientific research?

This equation is commonly used in thermodynamics and heat transfer research to calculate the final temperature of a system when two objects with different initial temperatures are brought into contact with each other. It is also used to analyze the efficiency of heat exchangers and other thermal processes.

5. Are there any limitations to this equation?

One limitation of this equation is that it assumes that the specific heat capacities of the objects involved are constant and do not change with temperature. In reality, specific heat capacities can vary with temperature, which can affect the accuracy of the calculated final temperature. Additionally, this equation does not take into account any heat loss or gain from the surroundings, which can also impact the accuracy of the results.

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