How Is Energy Calculated in a Perfectly Inelastic Collision Between Protons?

[mike217]

Hello Everyone,

Can you please help me with this problem. I am not looking for a complete solution to it, I just need a few guidelines on how to proceed. Here it is,

Let us consider a perfectly inelastic collision between two protons: an incident proton with mass m, kinetic energy K, and momentum magnitude p joins with an originally stationary target proton to form a single product particle of mass M. Show that the energy available to create a product particle is given by,

Mc^2=2mc^2(1+K/(2mc^2))^1/2

Thank you.

 

[dextercioby]

The total energy of the incoming protons is obviously
[tex] E=2mc^{2}+K=2mc^{2}(1+\frac{K}{2mc^{2}}) [/tex]

I don't know what your formula means...

Daniel.

 

[wais]

Sure, I can give you some guidelines on how to approach this problem. Firstly, it is important to understand the concept of inelastic collisions. In an inelastic collision, kinetic energy is not conserved and is converted into other forms of energy, such as heat or sound. In this case, the two protons will stick together and form a single product particle.

To solve this problem, you will need to use conservation of momentum and conservation of energy principles. Let's start by writing the equations for these principles:

Conservation of momentum:
p_initial = p_final

Conservation of energy:
K_initial = K_final + ΔE

Where p is momentum, K is kinetic energy, and ΔE is the change in energy during the collision. In this case, we know that the initial momentum is given by p = mvp, where m is the mass of the proton, v is its velocity, and p is its momentum magnitude. The final momentum will be the same for the product particle, but since it is now a single particle, we can write it as p = Mv', where M is the mass of the product particle and v' is its velocity.

Using the conservation of momentum equation, we can write:
mvp_initial = Mv'p_final

Since the initial proton is the only one with kinetic energy, we can write the conservation of energy equation as:
K_initial = K_final + ΔE

Now, we need to find a way to express the final kinetic energy and the change in energy in terms of the given variables. To do this, we can use the fact that the final velocity of the product particle can be expressed in terms of the initial velocities of the two protons:

v' = (mvp_initial + 0)/M

Substituting this into the conservation of momentum equation, we get:
mvp_initial = M(mvp_initial + 0)

Solving for vp_initial, we get:
vp_initial = (M/m)vp_initial

Now, we can use this to express the final kinetic energy as:
K_final = (M/m)^2K_initial

And the change in energy as:
ΔE = (M/m - 1)K_initial

Substituting these into the conservation of energy equation, we get:
K_initial = (M/m)^2K_initial + (M/m - 1)K_initial

Simplifying, we get:
K_initial = (M/m