How Is Angular Speed Calculated for a Chain Saw Sprocket?

[wallace13]

The drawing (attached) shows the blade of a chain saw. The rotating sprocket tip at the end of the guide bar has a radius of 3.8 10-2 m. The linear speed of a chain link at point A is 6.5 m/s. Find the angular speed of the sprocket tip in rev/s.


Vt= w/r


6.5= w/ .038

w=.247 rev/ sec

.247 was incorrect and I am unsure of what I am missing from my equation

 

[glueball8]

hmm your formula is wrong

[tex] V=\omega \times R [/tex]

 

[thomate1]

. Can you explain why my answer may be incorrect?Your equation for calculating the angular speed (w) of the sprocket tip is correct. However, the problem lies in the units that were used. The linear speed (Vt) is given in meters per second (m/s) while the radius (r) is given in meters (m). To use the equation correctly, the units must be consistent. In this case, the radius should be converted to meters by dividing it by 100 (since 1 cm = 0.01 m). So the correct equation would be:

Vt = w/(.038/100)

Solving for w, we get:

w = 6.5 * (.038/100)

w = 0.00247 rev/s

Therefore, the angular speed of the sprocket tip is 0.00247 revolutions per second.