How Electromotive Force is Produced by Electric Generator?

In summary, the conversation discusses the concept of Electromotive Force, also known as the Lorentz force, which is responsible for the movement of electrons in one direction to create an electric current. It is also mentioned that this force causes protons to group at the top and electrons at the bottom, depending on the direction of the magnetic field. The formula for calculating electromotive force is also mentioned, which involves dividing the energy by the amount of charge. The conversation also touches upon Faraday's Law of induction, which involves the integral form of the Lorentz force and the velocity field of the path.
  • #1
mo0nfang
13
0
at 5:42 - What is Electromotive Force? Why does it make electrons move (make electric current) in one direction?
 
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  • #2
That force is called the Lorentz force, which google.
 
  • #3
Electromagnetic Induction @1:40 <--- Why protons group themselves at the top and electrons at the bottom?
 
  • #4
mo0nfang said:
Electromagnetic Induction @1:40 <--- Why protons group themselves at the top and electrons at the bottom?
In that video, the electrons (-) are moving to the top. It's because of the direction of the magnetic field. It could have been either way.
 
  • #5
mo0nfang said:
Electromagnetic Induction @1:40 <--- Why protons group themselves at the top and electrons at the bottom?
Again, it is the Lorentz force, of which you are well aware.
 
  • #6
mo0nfang said:
What is Electromotive Force?
How concentrated energy is in an electric field. Lorentz force moves charged particles to positions of higher potential energy.
Divide the energy by the amount of charge and you get electromotive force.
 
  • #7
To argue with a "potential" is misleading in this case since the Lorentz force is not a potential force but reads
$$\vec{F}=q \left (\vec{E}+\frac{\vec{v}}{c} \times \vec{B} \right),$$
and thus the correct electromotive force in Faraday's Law of induction in integral form is
$$\mathcal{E}(t)=\int_{C} \mathrm{d} \vec{r} \cdot \left [\vec{E}(t,\vec{x})+\frac{\vec{v}(t,\vec{x})}{c} \times \vec{B}(t,\vec{x}) \right ]=-\frac{1}{c} \dot{\Phi}_B,$$
where $$\vec{v}(t,\vec{x})$$ is the velocity field of the path ##C##.
 
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Related to How Electromotive Force is Produced by Electric Generator?

1. What is electromotive force (EMF)?

Electromotive force, also known as voltage, is the potential difference between two points in an electric circuit. It is measured in volts and is responsible for the flow of electric current.

2. How is electromotive force produced by an electric generator?

An electric generator produces EMF through electromagnetic induction. This process involves rotating a conductor within a magnetic field, which creates a changing magnetic flux. This changing magnetic flux induces an electric current in the conductor, producing an EMF.

3. What factors affect the amount of EMF produced by an electric generator?

The amount of EMF produced by an electric generator is affected by several factors, including the strength of the magnetic field, the speed of rotation of the conductor, the number of turns in the conductor, and the resistance of the circuit.

4. Can EMF be produced without a magnetic field?

No, EMF cannot be produced without a magnetic field. The process of electromagnetic induction, which is responsible for producing EMF, relies on the interaction between a magnetic field and a conductor.

5. How is EMF related to electric current?

EMF is directly related to electric current, as it is the force that drives the flow of electric charges in a circuit. The higher the EMF, the stronger the push on the charges, resulting in a higher electric current.

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