How Does the Steady Flow Energy Equation Apply to an Adiabatic Steam Turbine?

In summary, to find the work done per kilogram of steam and the mass flow rate, we first need to determine the specific enthalpy at the given inlet and exit conditions. Then, we can calculate the change in elevation and kinetic energy. Using the first law of thermodynamics, we can then find the work done per kilogram of steam. Finally, the power output of the turbine can be used to calculate the mass flow rate. I hope this helps clarify the steps to solve this problem. Please let me know if you need any further assistance.
  • #1
AMEY PHADKE
1
0

Homework Statement


The power output of an adiabatic steam turbine is 5 MW and inlet and exit conditions are as under
Given Inlet Pressure 2MPa Temprature 400 DEGREE CELSIUS Velocity 50m/s Elevation 10m
Exit Pressure 15 KPa Temprature 0.9 dry Velocity 180m/s Elevation 6 m
Determine the work done /kg of steam and the mass floe rate in kg/s

Homework Equations


Q-W=m(h2+v2^2/2+gZ2)-m(h1+v1^2/2+gz1) J/s

The Attempt at a Solution



I attempted to solve but can not under stand the meaning of .9 dry & how to find z1 and z2 pl. help
 
Physics news on Phys.org
  • #2


Thank you for providing the necessary information to solve this problem. Let's break down the steps to find the work done per kilogram of steam and the mass flow rate:

1. Determine the specific enthalpy at the inlet and exit conditions:
Using steam tables or a steam properties calculator, we can find the specific enthalpy at the given inlet and exit conditions. The specific enthalpy (h) is a measure of the energy of the steam per unit mass and is usually given in units of kJ/kg.

h1 = 3218 kJ/kg (inlet condition)
h2 = 269 kJ/kg (exit condition)

2. Find the change in elevation:
The change in elevation (Δz) is given by the difference in elevation between the inlet and exit conditions. In this case, Δz = 6m - 10m = -4m (since the exit elevation is lower than the inlet elevation).

3. Calculate the change in kinetic energy:
The change in kinetic energy (ΔKE) is given by the difference in velocity between the inlet and exit conditions. In this case, ΔKE = (180 m/s)^2/2 - (50 m/s)^2/2 = 12,250 kJ/kg.

4. Calculate the work done:
Using the first law of thermodynamics, we can calculate the work done per kilogram of steam as follows:

W = Q - m(h2 + ΔKE + gΔz) + m(h1 + ΔKE + gΔz)
where Q is the heat transfer, which is equal to zero in an adiabatic process.

W = -m(h2 - h1) + mΔKE + mgΔz
W = m(h1 - h2) + mΔKE + mgΔz
W = 3218 kJ/kg - 269 kJ/kg + 12,250 kJ/kg + (9.8 m/s^2)(-4m)
W = 14,199 kJ/kg

5. Calculate the mass flow rate:
The power output of the turbine is given as 5 MW, which is equal to 5,000,000 J/s. We can use this information to calculate the mass flow rate (m) as follows:

5,000,000 J/s = m(14,199 kJ/kg)
m = 0
 

Related to How Does the Steady Flow Energy Equation Apply to an Adiabatic Steam Turbine?

1. What is the Steady Flow Energy Equation?

The Steady Flow Energy Equation is a fundamental equation in thermodynamics that describes the conservation of energy in a steady flow system. It is used to analyze and solve problems related to energy transfer in fluid flow, such as in pipes, turbines, and heat exchangers.

2. How is the Steady Flow Energy Equation derived?

The Steady Flow Energy Equation is derived from the First Law of Thermodynamics, which states that energy cannot be created or destroyed, only transferred or converted from one form to another. By applying this law to a steady flow system and considering all forms of energy, the Steady Flow Energy Equation is obtained.

3. What are the assumptions made in the Steady Flow Energy Equation?

The Steady Flow Energy Equation makes several assumptions, including steady flow conditions (no changes in flow rate or properties over time), no work done on or by the system, and no heat transfer across the system boundaries. It also assumes that the fluid is incompressible and behaves as an ideal fluid.

4. How is the Steady Flow Energy Equation applied in real-world situations?

The Steady Flow Energy Equation is used in various engineering fields, such as in the design and analysis of power plants, refrigeration systems, and hydraulic systems. It is also used to optimize energy efficiency and identify areas of energy loss in these systems.

5. What are the limitations of the Steady Flow Energy Equation?

The Steady Flow Energy Equation has limited applicability in non-steady flow systems and situations where there is significant heat transfer or work done on the system. It also does not take into account irreversible processes, friction, and other real-world factors that may affect energy transfer. Therefore, it should be used with caution and validated with experimental data in practical applications.

Similar threads

  • Engineering and Comp Sci Homework Help
Replies
11
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
2
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
17
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
1
Views
722
  • Engineering and Comp Sci Homework Help
Replies
6
Views
7K
  • Engineering and Comp Sci Homework Help
Replies
1
Views
761
  • Engineering and Comp Sci Homework Help
Replies
4
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
5
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
1
Views
598
  • Introductory Physics Homework Help
Replies
11
Views
3K
Back
Top