- #1
toneboy1
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This is for an assignment, (not sure if its in the right section) but anyway I'm considering the system response to H(w) = 10/(jw + 10)
when the input is x(t) = 2 + 2*cos(50*t + pi/2)
so I know that Y(w) = X(w).H(w) but I'm not sure what to do about the '2 + ' in the input.
I know that '1' transforms into 2piδ(w) frequency domain.
so does this mean that 2 becomes 4piδ(w) ? times by H(w)...?
And if so, does this mean it in x(t) is only 4pi at w = 0 ? Because the w = 50 from that input.
Alternatively I concidered 2*H(0) or 2*H(50), but I see no reason for them.
My calculation would be as follows:
% y(t) = 2*something??* + |H(50)|*2.*cos(50*t + pi/2 + <H(50) )
%
% where <H(50) = ( 10<0 / 50.99<78.69 )
% and 360 - 78.69 = 281.31 and plus pi/2 that equals 11.31 deg
% in rad that is 0.197
%
% y(t) = 2 + 0.392*cos(50*t + 0.197)
Please help asap!
Thanks
when the input is x(t) = 2 + 2*cos(50*t + pi/2)
so I know that Y(w) = X(w).H(w) but I'm not sure what to do about the '2 + ' in the input.
I know that '1' transforms into 2piδ(w) frequency domain.
so does this mean that 2 becomes 4piδ(w) ? times by H(w)...?
And if so, does this mean it in x(t) is only 4pi at w = 0 ? Because the w = 50 from that input.
Alternatively I concidered 2*H(0) or 2*H(50), but I see no reason for them.
My calculation would be as follows:
% y(t) = 2*something??* + |H(50)|*2.*cos(50*t + pi/2 + <H(50) )
%
% where <H(50) = ( 10<0 / 50.99<78.69 )
% and 360 - 78.69 = 281.31 and plus pi/2 that equals 11.31 deg
% in rad that is 0.197
%
% y(t) = 2 + 0.392*cos(50*t + 0.197)
Please help asap!
Thanks