How Does Height Affect Weight in a Hypothetical Mile-High Building?

  • Thread starter dominus96
  • Start date
  • Tags
    Gravity
In summary, the conversation discusses the proposal of a mile-high building in Chicago by Frank Lloyd Wright in 1956 and the hypothetical change in weight experienced by an individual riding an elevator from street level to the top of the building, ignoring Earth's rotation. The conversation also includes an attempt at a solution using the equation g = Gm/R^2, but it is determined that the values for G and the mass of the Earth are not necessary and the fractional change in g can be determined using the distance to the center of Earth.
  • #1
dominus96
51
0

Homework Statement



In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constructed. Ignoring Earth's rotation, find the change in your weight if you were to ride an elevator from the street level, where you weigh 520 N, to the top of the building.

Homework Equations



a = Gm/R^2

The Attempt at a Solution



g = Gm/R^2, so I used 6.67E-11 for G, the mass of the Earth (5.97E24) for m, and the radius of the Earth plus the distance from Earth's surface (1 mile, which is about 1609 meters) for R. I calculated all that and got about 9.77 for g and then found weight and subtracted it from 520, but it was wrong. What's the deal?
 
Physics news on Phys.org
  • #2
You don't need the mass of the Earth, nor the value of G: the fractional change in g (which gives you the fractional change in weight) equals the fractional change in 1/r^2, with r the distance to the center of Earth (so, that number you do need).

The fractional change in g that you get is way too large (rounding errors?).
 
  • #3


There could be a few reasons why your answer may be incorrect. Firstly, it's important to note that the equation you used, a = Gm/R^2, gives the acceleration due to gravity, not the actual weight. To find the change in weight, you would need to use the formula F = ma, where F is the force of gravity, m is the mass of the object, and a is the acceleration due to gravity.

Secondly, you may have used the incorrect value for the mass of the Earth. The mass of the Earth is actually 5.97E24 kg, not 5.97E24. This could have affected your final answer.

Lastly, it's possible that the problem is asking for the change in weight due to the building's construction, not just the change in weight from being at a higher altitude. In this case, you would need to take into account the additional mass of the building and its effect on the gravitational force.

It's important to double check your calculations and make sure you are using the correct equations and values. If you are still having trouble, it may be helpful to consult with a teacher or classmate for assistance.
 

Related to How Does Height Affect Weight in a Hypothetical Mile-High Building?

1. Why do objects fall to the ground?

Objects fall to the ground because of the force of gravity. Gravity is a fundamental force of nature that pulls objects towards each other. The larger the mass of an object, the stronger its gravitational pull.

2. Why do some objects fall faster than others?

The rate at which objects fall is determined by their mass and the force of gravity. Objects with a larger mass have a greater gravitational pull and therefore fall faster than objects with a smaller mass.

3. Why do astronauts float in space if there is still gravity?

Astronauts float in space because they are in a state of freefall around the Earth. The Earth's gravitational pull is still present in space, but the astronauts are falling towards the Earth at the same rate as the space station, giving the illusion of weightlessness.

4. Why does gravity pull objects towards the center of the Earth?

Gravity pulls objects towards the center of the Earth because of the Earth's mass and density. The Earth's mass creates a strong gravitational pull, while its density causes objects to be pulled towards the center of the Earth where the mass is concentrated.

5. Why do objects feel heavier near the Earth's surface?

Objects feel heavier near the Earth's surface because the force of gravity is strongest near the Earth's surface. As objects get closer to the Earth's surface, the gravitational pull increases, making them feel heavier.

Similar threads

  • Introductory Physics Homework Help
Replies
4
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
5K
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
13
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
769
  • Introductory Physics Homework Help
Replies
4
Views
3K
  • Introductory Physics Homework Help
Replies
5
Views
3K
Replies
6
Views
5K
Back
Top