How Does Earth's Curvature Affect Projectile Motion Calculations?

[Vash2940]

Hello, I am in a General Physics class and I am having trouble understanding this question. There aren't any similar examples in my book either. I am not looking for the solution, just a step in the direction.

I don't really know where to start or how to begin the proof process.

Homework Statement

The curvature of the Earth becomes important in projectile calculations when the distance traveled R, is a significant fraction of the radius of the earth, Re. Ignoring any possible variations in g, show that (a) the extra time the projectile is in motion is approximately given by (delta)t = delta(y)/V0y(initial y velocity) = R^2/2Re/V0y; (b) the fractional error (delta)R/R is given by (delta)R/R = V0x^2/gRe.

Homework Equations

Look at the end of the question.

The Attempt at a Solution

I am new here, so forgive me if this format isn't correct, Ill be sure to fix it right away

Thanks!

 

[jbsteele]

The first step to solving this problem would be to familiarize yourself with the relevant equations and concepts. You will need to understand projectile motion, the equations of motion, and the curvature of the Earth. Additionally, you will need to know how to calculate the time and fractional error of a projectile's motion. Once you have all of this information, you can begin to work through the problem. Start by writing down the equations of motion for a projectile, which will include the initial conditions and the acceleration due to gravity. Then, use these equations to calculate the extra time (delta)t and the fractional error (delta)R/R. Finally, substitute the values given in the question for R, Re, V0y, and g to calculate the two answers.