- #1
Virtate
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How do you do this proof? Isn't it already obvious given the definition? I have no idea how to go about writing it down. If someone could help me with this, I would really appreciate it. Thanks :) Sorry I had to write it in such a messy way.
Define the closure of A as A closure = (x|for every open rectangle u containing x, intersection of u and A not equal to 0)
a) Show that A closure = A union bdA
b) Prove that bdA = intersection of A closure and (R^n-A) closure = bd(R^n-A)
Define the closure of A as A closure = (x|for every open rectangle u containing x, intersection of u and A not equal to 0)
a) Show that A closure = A union bdA
b) Prove that bdA = intersection of A closure and (R^n-A) closure = bd(R^n-A)
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