How Do You Integrate Cosine Powers in Calculus?

In summary: C is a constant. In summary, the integral of cos^(2n+1)(x) can be expressed as a polynomial of degree (2n+1) in sin(x) using the binomial theorem and linearity of the integral. The answer is given by \sin(x)-\frac { n{ \sin }^{ 3 }(x) }{ 3 } +...+\frac { { (-1) }^{ n }{ \sin }^{ 2n+1 }(x) }{ 2n+1 } +C.
  • #1
golanor
59
0

Homework Statement



[itex]\int { { cos }^{ 2n+1 }(x)dx } [/itex]

Homework Equations


[itex]{ cos }^{ 2 }+{ sin }^{ 2 } = 1 [/itex]

The Attempt at a Solution


i got to here:
[itex]\int { { (1-{ sin }^{ 2 }(x)) }^{ n }d(sin(x)) } [/itex]

Any help would be appreciated!
 
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  • #2
So you got to find

[tex]\int (1-x^2)^ndx.[/tex]

Use the binomial theorem and linearity of the integral.
 
  • #3
golanor said:

Homework Statement



[itex]\int { { cos }^{ 2n+1 }(x)dx } [/itex]

Homework Equations


[itex]{ cos }^{ 2 }+{ sin }^{ 2 } = 1 [/itex]

The Attempt at a Solution


i got to here:
[itex]\int { { (1-{ sin }^{ 2 }(x)) }^{ n }d(sin(x)) } [/itex]

Any help would be appreciated!

There is no simple formula for the result, unless you want to express it in terms of a hypergeometric function. The answer is a polynomial of degree (2n+1) in ##\sin(x)##.

BTW: in [t e x] you should write "\sin(x)" instead of "sin(x)": the difference is ##\sin(x)## (nice) vs. ##sin(x)## (not nice).
 
  • #4
Ray Vickson said:
There is no simple formula for the result, unless you want to express it in terms of a hypergeometric function. The answer is a polynomial of degree (2n+1) in ##\sin(x)##.

BTW: in [t e x] you should write "\sin(x)" instead of "sin(x)": the difference is ##\sin(x)## (nice) vs. ##sin(x)## (not nice).
Thanks for the tex hint..still getting the hang of it (used to microsoft equation editor =\)

micromass said:
So you got to find

[tex]\int (1-x^2)^ndx.[/tex]

Use the binomial theorem and linearity of the integral.
Thanks, i actually read about it, thought that i should use it but decided not to.

In case anyone wants the answer, it is:
[tex]\int { { (1-{ \sin }^{ 2 }(x)) }^{ n }d(\sin (x)) } =\sin (x)-\frac { n{ \sin }^{ 3 }(x) }{ 3 } +...+\frac { { (-1) }^{ n }{ \sin }^{ 2n+1 }(x) }{ 2n+1 } +C[/tex]
 

Related to How Do You Integrate Cosine Powers in Calculus?

1. What is the definition of integration of cosine?

The integration of cosine is a mathematical process that involves finding the area under the curve of a cosine function. It is a fundamental concept in calculus and is used to solve a variety of problems in physics, engineering, and other fields.

2. How do you integrate cosine?

To integrate cosine, you need to use the integration formula, which is ∫cos(x) dx = sin(x) + C, where C is a constant of integration. You can also use integration techniques such as substitution, integration by parts, or trigonometric identities to simplify the integral.

3. What are the applications of integrating cosine?

The integration of cosine has many applications in mathematics, physics, and engineering. It is used to find the displacement, velocity, and acceleration of an object in motion, as well as the area under a curve and the volume of a solid of revolution. It is also used in the study of waves, vibrations, and other periodic phenomena.

4. What is the difference between indefinite and definite integration of cosine?

Indefinite integration of cosine results in a general solution, while definite integration gives a specific value. Indefinite integration is used to find the antiderivative of a function, while definite integration is used to find the area under a curve between two points on the x-axis.

5. What are some common mistakes to avoid when integrating cosine?

Some common mistakes to avoid when integrating cosine include forgetting to add the constant of integration, making errors in the substitution process, and forgetting to change the limits of integration when using definite integration. It is also important to check for symmetry and use the correct trigonometric identities when simplifying the integral.

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