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Lens Help Needed!
A converging lens with a focal length of 50cm and a diverging lens with a focal length of -52 cm are 227cm apart. A 3.9-cm-tall object is 70cm in front of the converging lens.
Calculate the distance between image and diverging lens.
Express your answer using two significant figures.
d = 26cm
correct
Part B
Calculate the image height.
Express your answer using two significant figures.
h = 1.3 wrong
one attempt remaing.
Work:
for final image distance:
1/f1 = 1/p1 + 1/q1
1/50 - 1/70 = 1/q1
q1 = 175 cm
227-175=52cm
1/f2 = 1/p2 + 1/q2
-1/52 - 1/52 = 1/q2
q2 = -26 -----> 26 cm final image distance
for image height:
M1 = -q1/p1 = 2.5
l-2.5l = h1(image)/h1(ogject)
9.75cm = h1(image)
M2 = -q2/p2 = .5
.5 = h2(image)/h1(image)
4.9 = h2(image)
is this right? I have only one attempt left
Please help...
A converging lens with a focal length of 50cm and a diverging lens with a focal length of -52 cm are 227cm apart. A 3.9-cm-tall object is 70cm in front of the converging lens.
Calculate the distance between image and diverging lens.
Express your answer using two significant figures.
d = 26cm
correct
Part B
Calculate the image height.
Express your answer using two significant figures.
h = 1.3 wrong
one attempt remaing.
Work:
for final image distance:
1/f1 = 1/p1 + 1/q1
1/50 - 1/70 = 1/q1
q1 = 175 cm
227-175=52cm
1/f2 = 1/p2 + 1/q2
-1/52 - 1/52 = 1/q2
q2 = -26 -----> 26 cm final image distance
for image height:
M1 = -q1/p1 = 2.5
l-2.5l = h1(image)/h1(ogject)
9.75cm = h1(image)
M2 = -q2/p2 = .5
.5 = h2(image)/h1(image)
4.9 = h2(image)
is this right? I have only one attempt left
Please help...