- #1
DaveC426913
Gold Member
- 22,530
- 6,192
OK, here's what I'm doing:
I currently have a single 20 watt halogen puck:
[PLAIN]http://www.lightingfx.com/media/images/product_category/ro29.jpg
powered through a rectifier from AC.
The reason I've done this is because I need the interrupt the AC with a light timer switch.
I want to toss out the 20watt halogen puck and substitute an LED puck light (IKEA, INREDA). So I'll be keeping the rectifier.
The new light from IKEA does not seem to be listed yet. (I remember when you could go to Ikea and trust that what you bought last time was still there.)
There are four pucks in a pack, each puck can be seen to have 18 LEDs. I only need 1 puck.
The power supply is listed as:
DC12V, max 500mA, 0.5-6W
DC700mA, max 8.5V.
I want to figure out how to wire this up in place of my halogen puck light. I know i'll need a resistor in series with the LEDs but does the fact that there are 18 of them change how I calculate it?
I currently have a single 20 watt halogen puck:
[PLAIN]http://www.lightingfx.com/media/images/product_category/ro29.jpg
powered through a rectifier from AC.
The reason I've done this is because I need the interrupt the AC with a light timer switch.
I want to toss out the 20watt halogen puck and substitute an LED puck light (IKEA, INREDA). So I'll be keeping the rectifier.
The new light from IKEA does not seem to be listed yet. (I remember when you could go to Ikea and trust that what you bought last time was still there.)
There are four pucks in a pack, each puck can be seen to have 18 LEDs. I only need 1 puck.
The power supply is listed as:
DC12V, max 500mA, 0.5-6W
DC700mA, max 8.5V.
I want to figure out how to wire this up in place of my halogen puck light. I know i'll need a resistor in series with the LEDs but does the fact that there are 18 of them change how I calculate it?
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