- #1
GreenPrint
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Homework Statement
I got down to here and didn't know where to go from here
http://www.wolframalpha.com/input/?...)(1-i^(-4/3))))(x+3/2(1+i^(2/3)(1-i^(-4/3))))
see the input value on that link if you don't feel like reading the equation below
(x-3) (x-3/2 (-1+i^(2/3) (1-i^(-4/3)))) (x+3/2 (1+i^(2/3) (1-i^(-4/3))))
now my question is how come wolfram tells me that the exact result is
(x-3) (x-3/2 ((-1)^(1/3) (1+(-1)^(1/3))-1)) (x+3/2 (1+(-1)^(1/3) (1+(-1)^(1/3))))
again click on the link to see the "exact result" if you don't want to read the equation like this
the two are not equal to each other by any means what's up with this?
Also the end result that I'm suppose to get to apparently is this
x^3+3/2 (1+e^((i pi)/3) (1+e^((i pi)/3))) x^2-3/2 (-1+e^((i pi)/3) (1+e^((i pi)/3))) x^2-3 x^2-9/4 (-1+e^((i pi)/3) (1+e^((i pi)/3))) (1+e^((i pi)/3) (1+e^((i pi)/3))) x-9/2 (1+e^((i pi)/3) (1+e^((i pi)/3))) x+9/2 (-1+e^((i pi)/3) (1+e^((i pi)/3))) x+27/4 (-1+e^((i pi)/3) (1+e^((i pi)/3))) (1+e^((i pi)/3) (1+e^((i pi)/3)))
the last alternate form on wolfram link above and currently I'm at the input form of x^3 - 27
(x-3) (x-3/2 (-1+i^(2/3) (1-i^(-4/3)))) (x+3/2 (1+i^(2/3) (1-i^(-4/3))))
any help in getting to that anser would be great as I don't know how to...