- #1
karush
Gold Member
MHB
- 3,269
- 5
Evaluate using a trig identity
$$\displaystyle
\int \dfrac{5}{x^2\sqrt{25-x^2}}\, dx$$
my first inclination to set
$u=5\sin{x}$
then
$du=5\cos{x}\, dx$ or $dx=\dfrac{du}{5\cos {x}}$
$$\displaystyle
\int \dfrac{5}{x^2\sqrt{25-x^2}}\, dx$$
my first inclination to set
$u=5\sin{x}$
then
$du=5\cos{x}\, dx$ or $dx=\dfrac{du}{5\cos {x}}$