Horrible expression involving logs and inverse tan functions

[coverband]

Homework Statement

[tex] \frac{d^2y}{dx^2} + (y^4-1)\frac{dy}{dx} = 0 [/tex]

Homework Equations

[tex] \frac{dy}{dx} + (y^4-1) = 0 [/tex]

The Attempt at a Solution

[tex] \frac{dy}{dx} = (1- y^4) [/tex]
[tex] \frac{dy}{1- y^4} = dx [/tex]

Then I get a horrible expression involving logs and inverse tan functions on the LHS and x + A on RHS ?

sorry heading should be ODE not PDE

 

[Klockan3]

You have the wrong expression after the integration, try taking the derivative of that with respect to x to see if you get the same expression as you started with. HINT: You forgot the x to y dependence.