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Ross891
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1. The problem statement, all variables and given/known
A conical Nozzle has a diameter on one end of 0.5m and 2m on the other. The nozzle is 6m long. The flow rate is 10 m/s. or 10m^3/s
We are assuming that the liquid is in compressible.
1. Calculate the flow rate at midpoint along the nozzle.
2. if the Fluid has a relative density of 0.866 calculate the mass flow rate
Flow rate = velocity x surface area
All I have done so Far on part a is worked out the rate of expansion of the cone by doing:
The difference in diameters is 1.5
So 1.5/6=0.25
So the cone expands 0.25 every meter.
Then I times the rate of expansion by half the length:
0.25x3=0.75
Then the surface area of the midpoint
PI x 1.25^2/4 = 1.227
The flow rate is 10 m/s flowing from left to right
So I've worked out the surface area of the midpoint of the tube to be 1.227.
And the velocity of the flow rate would be 8.1499. Flow rate/surface area.
Then 8.1499x1.227=9.999 which is the flow rate through that point. But that doesn't seem right. If you knew the flow rate was constant through the pipe what is the point of calculation?
Have I missed a step? I'm only doing part a at the moment. Once I solve this I will move onto B
A conical Nozzle has a diameter on one end of 0.5m and 2m on the other. The nozzle is 6m long. The flow rate is 10 m/s. or 10m^3/s
We are assuming that the liquid is in compressible.
1. Calculate the flow rate at midpoint along the nozzle.
2. if the Fluid has a relative density of 0.866 calculate the mass flow rate
Homework Equations
Flow rate = velocity x surface area
The Attempt at a Solution
All I have done so Far on part a is worked out the rate of expansion of the cone by doing:
The difference in diameters is 1.5
So 1.5/6=0.25
So the cone expands 0.25 every meter.
Then I times the rate of expansion by half the length:
0.25x3=0.75
Then the surface area of the midpoint
PI x 1.25^2/4 = 1.227
The flow rate is 10 m/s flowing from left to right
So I've worked out the surface area of the midpoint of the tube to be 1.227.
And the velocity of the flow rate would be 8.1499. Flow rate/surface area.
Then 8.1499x1.227=9.999 which is the flow rate through that point. But that doesn't seem right. If you knew the flow rate was constant through the pipe what is the point of calculation?
Have I missed a step? I'm only doing part a at the moment. Once I solve this I will move onto B