- #1
riseofphoenix
- 295
- 2
Ok so I tried making myself a free-body diagram but I reached a dead end..
Step 1) fkinetic = μkn
fkinetic = μk(251)
fkinetic / 251 = μk
Step 2)
Fx:
T1
Fy
n = (m)(g) = 251 N
120.5 N
Step 3)
ƩFx = m(-a) since it's moving the left or ƩFx = 0 (since it's moving at CONSTANT velocity)
ƩFy = ma
Step 4)
ƩFy: 251 + 120.5 = (25.58 + 12.28)a
*** I got the masses by solving 120.5 = m(9.81) and 251 = m(9.81) ***
ƩFy: 371.5 = (37.86)a
ƩFy: 371.5/37.86 = a
ƩFy: 9.81 = aStep 5)
T1 = m(-a)
T1 = (25.58)(-9.81) = 250.9 = 251 :(
Help?