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- Jan 26, 2012

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Hi kmooney,you need to put the 1/2x on both sides

Just to confirm, is this the equation?

\(\displaystyle 15+\frac{1}{2}=0.60(20x)\)

Or is it \(\displaystyle 15+\frac{1}{2x}=0.60(20x)\)

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Do you mean \(\displaystyle \frac{1}{2}x\) or \(\displaystyle \frac{1}{2x}\)?

And where in the original equation do you see anything like that? If it were me, I would combine terms on the left side and distribute the 0.60 on the right. What do you get after doing this?

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I would simply add the 1/2 to the 15, and multiply the 0.60 with the 20...what does the equation look like now?

edit: I have retitled this topic to indicate the type of problem for which help is being asked. A topic title ideally will indicate the nature of the problem being discussed.

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No, while we can mutiply across when multiplying fractions, we cannot add across when adding them. We need to get a common denominator, then put the sum of the numerators over this common denominator. For example:15/1+1/2=16/3

\(\displaystyle 3+\frac{1}{3}=\frac{9}{3}+\frac{1}{3}=\frac{9+1}{3}=\frac{10}{3}\)

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Why would you first subtract through by $\dfrac{1}{2}$? It is okay, but seems overly complicated, to then have to add it back after multiplying through by 2.15+ 1/2 =0.60(20x)

multiply 0.60(20x)=12.00x

The answer be 12x

15+ 1/2=12x

15=12x-1/2 hence a+b=c then a=c-b

find LCM of 2 and 1

then [24x-1]/2

15=[24x-1]/2

15*2=24x-1 hence a/b=c then a=bc

30=24x-1

31=24x

x=31/24

I would proceed as follows:

\(\displaystyle 15+\frac{1}{2}=12x\)

Combine terms on the left:

\(\displaystyle \frac{31}{2}=12x\)

Multiply through by 2:

\(\displaystyle 31=24x\)

Divide through by 24, and arrange as:

\(\displaystyle x=\frac{31}{24}\)

- Oct 16, 2012

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\(\displaystyle 15+\frac{1}{2}=0.60(20x)\)

I would begin by first multiplying the \(\displaystyle 20x\) by the \(\displaystyle 0.60\).

As such we would have,

\(\displaystyle 15+\frac{1}{2}=12x\)

Then we would need to condense the left side of the equation.

\(\displaystyle \frac{31}{2}=12x\)

Then I would divide the 12 over.

\(\displaystyle \frac{1}{12}\times(\frac{31}{2})=(12x)\times \frac{1}{12}\)

Then we would get the final answer that everyone else has arrived at!

\(\displaystyle x=\frac{31}{24}\)

- Mar 12, 2014

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Solve for x and then your need to distribute the numbers to get the value of the variable.