Heat Capacity energy exchange problem

In summary, the final temperature of the water for Mr. Gryphon's tea was 94 degrees Celsius, calculated using the equation Qreleased+Qabsorbed=0 and the given heat capacities for water and porcelain.
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sww_world
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Homework Statement
Mr. Gryphon was taking a break between classes and decided to make himself a cup of tea. He poured 250g of water at 95°C into an 85g porcelain mug which had an initial temperature of 19°C. What was the final temperature of the water for his tea? ( Not technically part of the question but the given heat capacities of water from a previous question was 4180 J/kg °C and porcelain was 107.)
Relevant Equations
Q=mc▲t, Qreleased + Qabsorbed = 0, T=Tf-Ti
Givens for water: m: 0.250kg of water
TW : 95°C
C=4180

Givens for mug: m=0.085kg
TM : 19°
c=107

Required: final temperature of water

Analysis/Solution: Qreleased+Qabsorbed=0, q=mc▲t

mw*cw*Tw + mp*cp*Tp = 0

(0.250)(4180) (T2-95) + (0.085)(107)(t2-19)=0

1045(t2-95) + 9.095(t2-19)=0

1045T2-99275 + 9.095T2-172.805=0

1054.095T2 - 99447.805 = 0

99447.805/1054.095 = t2

t2=94

Statement: The final temperature of the water for his tea was 94 degreesI'm not sure here if what I did with the temperature was correct, or if I made a mistake somewhere else. (I would also appreciate if you guys tell me if my formatting is acceptable/too hard too look at?)
 
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  • #2
sww_world said:
Problem Statement: Mr. Gryphon was taking a break between classes and decided to make himself a cup of tea. He poured 250g of water at 95°C into an 85g porcelain mug which had an initial temperature of 19°C. What was the final temperature of the water for his tea? ( Not technically part of the question but the given heat capacities of water from a previous question was 4180 J/kg °C and porcelain was 107.)
Relevant Equations: Q=mc▲t, Qreleased + Qabsorbed = 0, T=Tf-Ti

Givens for water: m: 0.250kg of water
TW : 95°C
C=4180

Givens for mug: m=0.085kg
TM : 19°
c=107

Required: final temperature of water

Analysis/Solution: Qreleased+Qabsorbed=0, q=mc▲t

mw*cw*Tw + mp*cp*Tp = 0

(0.250)(4180) (T2-95) + (0.085)(107)(t2-19)=0

1045(t2-95) + 9.095(t2-19)=0

1045T2-99275 + 9.095T2-172.805=0

1054.095T2 - 99447.805 = 0

99447.805/1054.095 = t2

t2=94

Statement: The final temperature of the water for his tea was 94 degreesI'm not sure here if what I did with the temperature was correct, or if I made a mistake somewhere else. (I would also appreciate if you guys tell me if my formatting is acceptable/too hard too look at?)
All good.
 
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Related to Heat Capacity energy exchange problem

1. What is heat capacity?

Heat capacity is the amount of heat energy required to raise the temperature of a substance by one degree Celsius. It is a measure of how much heat a substance can absorb before its temperature changes.

2. How is heat capacity different from specific heat?

Heat capacity is a property of a substance, while specific heat is a specific value for a particular substance. Heat capacity is dependent on the mass and composition of a substance, while specific heat is a constant value for a given substance.

3. What factors affect heat capacity?

The two main factors that affect heat capacity are the mass and composition of a substance. Other factors that can also have an impact include temperature, pressure, and the state of matter (solid, liquid, or gas).

4. How do you calculate heat capacity?

Heat capacity can be calculated by dividing the amount of heat energy transferred to a substance by the change in temperature of the substance. The formula is C = Q/ΔT, where C is the heat capacity, Q is the heat energy, and ΔT is the change in temperature.

5. Why is heat capacity important in energy exchange problems?

Heat capacity is important in energy exchange problems because it determines how much heat energy is required to raise the temperature of a substance. It is also used to calculate the amount of heat transfer in a system, which is crucial in understanding and predicting thermal behavior and processes.

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