- #1
sww_world
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- Homework Statement
- Mr. Gryphon was taking a break between classes and decided to make himself a cup of tea. He poured 250g of water at 95°C into an 85g porcelain mug which had an initial temperature of 19°C. What was the final temperature of the water for his tea? ( Not technically part of the question but the given heat capacities of water from a previous question was 4180 J/kg °C and porcelain was 107.)
- Relevant Equations
- Q=mc▲t, Qreleased + Qabsorbed = 0, T=Tf-Ti
Givens for water: m: 0.250kg of water
TW : 95°C
C=4180
Givens for mug: m=0.085kg
TM : 19°
c=107
Required: final temperature of water
Analysis/Solution: Qreleased+Qabsorbed=0, q=mc▲t
mw*cw*Tw + mp*cp*Tp = 0
(0.250)(4180) (T2-95) + (0.085)(107)(t2-19)=0
1045(t2-95) + 9.095(t2-19)=0
1045T2-99275 + 9.095T2-172.805=0
1054.095T2 - 99447.805 = 0
99447.805/1054.095 = t2
t2=94
Statement: The final temperature of the water for his tea was 94 degreesI'm not sure here if what I did with the temperature was correct, or if I made a mistake somewhere else. (I would also appreciate if you guys tell me if my formatting is acceptable/too hard too look at?)
TW : 95°C
C=4180
Givens for mug: m=0.085kg
TM : 19°
c=107
Required: final temperature of water
Analysis/Solution: Qreleased+Qabsorbed=0, q=mc▲t
mw*cw*Tw + mp*cp*Tp = 0
(0.250)(4180) (T2-95) + (0.085)(107)(t2-19)=0
1045(t2-95) + 9.095(t2-19)=0
1045T2-99275 + 9.095T2-172.805=0
1054.095T2 - 99447.805 = 0
99447.805/1054.095 = t2
t2=94
Statement: The final temperature of the water for his tea was 94 degreesI'm not sure here if what I did with the temperature was correct, or if I made a mistake somewhere else. (I would also appreciate if you guys tell me if my formatting is acceptable/too hard too look at?)