Gradient of an inverse vector function?

[CAF123]

Homework Statement

Consider [tex] f(\vec{x}) = |\vec{x}|^r, [/tex] where [itex] \vec{x} \in ℝ^n [/itex] and [itex] r \in ℝ[/itex].
Find [itex] \vec{∇}f [/itex]

The Attempt at a Solution

I know a vector function maps real numbers to a set of vectors, but here I believe we have the opposite. (inverse of a vector function, assuming inverse exists?)
I am unsure of where to go next.

 

[Dr. T]

Assuming the usual Euclidean norm on ℝ^n, the output is just a scalar. Computing the gradient, then, is a matter of taking partial derivatives. For example, the first component of the gradient is the partial of f with respect to x_1. If f= (sqrt(x_1^2 + ... + x_n^2))^r = (x_1^2 + ... + x_n^2) ^ (r/2) then the partial with respect to x_1 is r/2(x_1^2 + ... + x_n^2)^(r/2-1)*(2x_1). Continuing in this fashion gives the gradient.