Gamma Ray Decay to potential watts

In summary, the conversation discusses the potential power that could be produced from gamma decay of 60 Co to 60 Ni, with a 100% conversion efficiency. It is noted that each gamma decay takes a very short time and the rates can be calculated from the mean lives of the processes. The actual power would depend on the activity and it would take an enormous activity to generate enough power to light up an electrical light bulb. It is also mentioned that the production of 60Co is too expensive to make this practical. There is a discussion about the methods of energy conversion, with the possibility of using high-energetic electrons or heat from the impact site. However, it is noted that there is currently no efficient method available.
  • #1
ANarwhal
59
0
I'm interested in calculating how much power (in Watts) could be produced (assuming a 100% conversion efficiency between Gamma Rays and electrical power) from gamma decay of a 60 Co -> 60 Ni.

How long would this reaction last? Just a few seconds or longer? Are there any decays that last for a long time?
 
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  • #2
Each gamma decay takes a very short time (order 10^-23 seconds iirc) ... it is a statistical rather than a continuous process.

You can work out the rates from the mean lives of the processes. Imagine you are driving a sensitive waterwheel with raindrops.
 
  • #3
As Simon mentioned, the actual power will depend upon the activity, which is decays per second. Multiply this by the energy per decay and you have energy per second, which is power. You'll find it takes an enormous activity to generate enough power to light up an electricl light bulb.
 
  • #4
Cobalt 60 decay emits two 1.3 MeV gammas and a 0.3 MeV beta. This is 4.5e-13 J per decay. To produce 60 W, you would thus need 1.3e14 decays per second. This is equal to 3615 Ci, or about 3 g of Co-60. Co-60 has a half-life of 5.2 years which means if the bulb initially produced 60 W, after 5.2 years it would produce 30 W, after 10.4 years - 15 W, etc.

Note that this 60 W cobalt-60 lightbulb would cause a dose of 500 R/hr (fatal) at a distance of 10 ft if unshielded. However with a 5 inch thick leaded glass shield surrounding the bulb, this could be reduced to 0.1 R/hr at 10 ft.

(using the Rad Pro Calculator here: http://www.radprocalculator.com/Gamma.aspx )
 
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  • #5
How were you planning to do the energy conversion? I could only think of using a heat engine driving an alternator, which would not necessarily be very efficient. Is there some 'direct conversion' method?
 
  • #6
When the gamma rays hit matter, they can produce high-energetic electrons. Maybe the efficiency can be improved if they are used directly to generate high voltage/low current, which is then converted to the needs of a lamp. In addition, the heat of the impact site can be used.
The production of 60Co is too expensive to make this practical in any way.
 
  • #7
mfb said:
When the gamma rays hit matter, they can produce high-energetic electrons. Maybe the efficiency can be improved if they are used directly to generate high voltage/low current, which is then converted to the needs of a lamp. In addition, the heat of the impact site can be used.
The production of 60Co is too expensive to make this practical in any way.

There's the rub, I'm afraid. It's the actual details that would have to be right and I don't think a method exists yet. As far as I know, the only methods available (used in spacecraft ) involve using a nuclear source for heat and then thermoelectric junctions - not very efficient.
 

Related to Gamma Ray Decay to potential watts

1. What is Gamma Ray Decay?

Gamma ray decay is a process in which an unstable atomic nucleus releases excess energy in the form of gamma rays, resulting in a more stable nucleus.

2. How does Gamma Ray Decay occur?

Gamma ray decay occurs when an unstable atomic nucleus, typically with too many protons or neutrons, undergoes a rearrangement of its internal structure in order to become more stable. This rearrangement releases excess energy in the form of gamma rays.

3. What is the relationship between Gamma Ray Decay and potential watts?

In gamma ray decay, the excess energy released is in the form of gamma rays which can be measured in terms of potential watts. Potential watts refer to the amount of energy released per unit of time. Therefore, gamma ray decay can be measured in terms of potential watts.

4. Can Gamma Ray Decay be used as a source of energy?

Yes, gamma ray decay can be used as a source of energy. The gamma rays released during the decay process can be harnessed and converted into electricity, making it a potential source of nuclear energy.

5. What are some practical applications of Gamma Ray Decay?

Gamma ray decay has several practical applications, including in nuclear power plants where it is used to generate electricity, in medical imaging for cancer treatment and diagnosis, and in industrial settings for sterilization and materials testing.

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