Frictional coin sliding on turntable

In summary, the conversation discusses the maximum rpm that a turntable can speed up to without a 5.0 g coin sliding off. The coin is placed 22 cm from the center of the turntable and has static and kinetic coefficients of friction with the turntable surface of µs = 0.80 and µk = 0.50. The equations v = angular velocity * r and Force(net) = m(v)^2 / r are mentioned, and it is noted that the coin will slip when the inertia is greater than the product of µs and the normal force. The conversation then suggests using the maximum value of the centripetal force in the equation to calculate the maximum speed and express it in rpm.
  • #1
Umphreak89
6
0
A 5.0 g coin is placed 22 cm from the center of a turntable. The coin has static and kinetic coefficients of friction with the turntable surface of µs = 0.80 and µk = 0.50. What is the maximum rpm that the turntable could speed up to without the coin sliding off?
m = .005 kg
r = .22 m
µs = 0.8

Equations found..
v = angular velocity * r
Force(net) = m(v)^2 / r

Inertia > µs N when coin slips (?)

I believe this gets set equal to mg (Normal Force) but I haven't been able to generate the correct answer multiplying µs as a coefficient of either side.

I'm not sure what isn't being accounted for, what do I do?
 
Last edited:
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  • #2
You're heading in the right direction. Answer these questions:
(1) What force provides the centripetal force on the coin?
(2) What's the maximum value of that force?

Use that maximum value of force in your centripetal force equation to calculate the maximum speed. Then express that answer in rpm.

Do Not Double Post!
 
Last edited:
  • #3


I would approach this problem by first identifying the key variables and equations involved. From the given information, we know that the coin has a mass of 0.005 kg and is placed 0.22 m from the center of the turntable. We also have the static coefficient of friction (µs = 0.8) and kinetic coefficient of friction (µk = 0.5).

Using the equations you have already identified, we can calculate the maximum angular velocity (ω) of the turntable before the coin starts to slide off. This can be found by equating the centrifugal force (mω^2r) to the maximum static friction force (µsN) where N is the normal force.

mω^2r = µsN

We can also express the normal force in terms of the weight of the coin (mg) since the coin is placed on a horizontal surface.

N = mg

Substituting this into the equation above, we get:

mω^2r = µsmg

Solving for ω, we get:

ω = √(µsg/r)

Plugging in the given values, we get:

ω = √(0.8*9.8/0.22) = 5.57 rad/s

To convert this to rpm, we multiply by 60/2π, giving us a maximum rpm of approximately 503 rpm.

In conclusion, the maximum rpm that the turntable could speed up to without the coin sliding off is 503 rpm. This calculation assumes that the turntable is accelerating uniformly and that the coin is placed at the edge of the turntable. Any changes in these conditions could affect the maximum rpm.
 

Related to Frictional coin sliding on turntable

1. What is friction and how does it affect a coin sliding on a turntable?

Friction is a force that opposes motion between two surfaces in contact. In the case of a coin sliding on a turntable, friction between the coin and the turntable's surface can slow down or stop the coin's motion.

2. What factors affect the amount of friction between a coin and a turntable?

The amount of friction between a coin and a turntable is affected by the type of surface the coin is sliding on, the weight of the coin, and the speed at which the turntable is spinning.

3. Can the amount of friction between a coin and a turntable be reduced?

Yes, the amount of friction can be reduced by using a smoother surface for the turntable, reducing the weight of the coin, and decreasing the speed of the turntable's rotation.

4. How does friction affect the trajectory of a coin sliding on a turntable?

Friction can cause a coin to veer off its intended path as it slides on a turntable. This is because the force of friction acts in the opposite direction of the coin's motion, causing it to slow down and change direction.

5. How is friction involved in the process of a coin coming to a stop on a turntable?

Friction plays a crucial role in the process of a coin coming to a stop on a turntable. As the coin slides and rubs against the turntable's surface, friction converts its kinetic energy into heat, causing it to slow down and eventually come to a stop.

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