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GalacticSnipes
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Homework Statement
A 25 kg bear slides, from rest, 8 m down a lodgepole pine tree, moving with a speed of 6.4 m/s just before hitting the ground
(a) What change occurs in the gravitational potential energy of the bear-Earth system during the slide?
W = F*D
W = (m*a)*D
W = 1960
(b) What is the kinetic energy of the bear just before hitting the ground?
KE = 0.5*m*v^2
KE = 512
(c) What is the average frictional force that acts on the bear?
Ei = m*g*h = 1960
Ef = 0.5*m*v^2
W = -Fk*h
Ei + W = Ef
1960 + (-Fk*h) = 512
-Fk = 120.67
Could someone check to see if i solved this correctly?
Thanks!