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hi I've got a problem that I've partially worked but don't understand the next part/have made a mistake?
f(x)=0 for -π<x<0 and f(x)=x for 0≤x≤π
i got a0=π/4 and an=0 and bn=0 if n is even and 2/n if n is odd
∞
so... f(x)= π/4 + ∑ (2/(2n+1)) * sin(2n+1) * π * x
n=0
now i need to show π/4 = 1 - 1/3 + 1/5 ... using suitable values of x
how would i go about doing this?
any help is much appreciated
hi I've got a problem that I've partially worked but don't understand the next part/have made a mistake?
f(x)=0 for -π<x<0 and f(x)=x for 0≤x≤π
i got a0=π/4 and an=0 and bn=0 if n is even and 2/n if n is odd
∞
so... f(x)= π/4 + ∑ (2/(2n+1)) * sin(2n+1) * π * x
n=0
now i need to show π/4 = 1 - 1/3 + 1/5 ... using suitable values of x
how would i go about doing this?
any help is much appreciated
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