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Acceleration (a or 9.8 for simplicity); initial velocity (vf); distance (d); Initial velocity (vi)
trying to find a formula to answer "how far would you have to fall to reach x speed" where x is input from user.
Is it possible to answer this using two steps, first find time then find distance?d = vi*t + 0.5*a*(t^2) // t isn't given (can it be found with vi,vf,a ?)
d = (0) + .5(9.8)(t^2)
d =4.9(t^2)
vf = a(t) + vi // seems it can
vf = 9.8(t) + 0
t= (vf-vi) / a
[tex]t = \frac{vf-vi}{a} [/tex]yea that worked; code ended up being
//first we must find time
time = speed / 9.806;
//now use time in a distance equation
height = (vi*time) + (0.5*9.8)*(time*time);
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//if you jump out of a plane going towards ground at 250mph , how long/far would it take to reach 120mph (or terminal velocity in a traditional skydiving formation) due to air resistance , what force is being applied to your body?
That's the next part I need help with.
trying to find a formula to answer "how far would you have to fall to reach x speed" where x is input from user.
Is it possible to answer this using two steps, first find time then find distance?d = vi*t + 0.5*a*(t^2) // t isn't given (can it be found with vi,vf,a ?)
d = (0) + .5(9.8)(t^2)
d =4.9(t^2)
vf = a(t) + vi // seems it can
vf = 9.8(t) + 0
t= (vf-vi) / a
[tex]t = \frac{vf-vi}{a} [/tex]yea that worked; code ended up being
//first we must find time
time = speed / 9.806;
//now use time in a distance equation
height = (vi*time) + (0.5*9.8)*(time*time);
-----
//if you jump out of a plane going towards ground at 250mph , how long/far would it take to reach 120mph (or terminal velocity in a traditional skydiving formation) due to air resistance , what force is being applied to your body?
That's the next part I need help with.
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