- #1
Taiki_Kazuma
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This question has been asked several times, but I don't want the answer (I can see the stupid answer...) I need help with my solution...
A large aquarium of height 5.00m is filled with fresh water to a depth of 2.00m. One wall of the aquarium consists of thick plastic 8.00m wide. By how much does the total force on that wall increase if the aquarium is next filled to a depth of 4.00m.
p = ρgh
p = F/A
A = hw
ρ = 0.998x103 kg/m3
g = 9.81 m/s2
h1 = 2.00m
h2 = 4.00m
w = 8.00m
ΔF = F2 - F1
ΔF = p2A2 - p1A1
ΔF = ρgh2A2 - ρgh1A1
ΔF = ρg (h2A2 - h1A1)
ΔF = ρg (h22w - h12w)
ΔF = ρgw (h22 - h12)
ΔF = (.998x103 kg/m3) (9.81 m/s2) (8.00m) [ (4.00m)2 - (2.00m)2 ]
ΔF = 9.40x105 N
Correct Answer: 4.71x105 N
Why am I double what the answer is suppose to be?
Homework Statement
A large aquarium of height 5.00m is filled with fresh water to a depth of 2.00m. One wall of the aquarium consists of thick plastic 8.00m wide. By how much does the total force on that wall increase if the aquarium is next filled to a depth of 4.00m.
Homework Equations
p = ρgh
p = F/A
A = hw
The Attempt at a Solution
ρ = 0.998x103 kg/m3
g = 9.81 m/s2
h1 = 2.00m
h2 = 4.00m
w = 8.00m
ΔF = F2 - F1
ΔF = p2A2 - p1A1
ΔF = ρgh2A2 - ρgh1A1
ΔF = ρg (h2A2 - h1A1)
ΔF = ρg (h22w - h12w)
ΔF = ρgw (h22 - h12)
ΔF = (.998x103 kg/m3) (9.81 m/s2) (8.00m) [ (4.00m)2 - (2.00m)2 ]
ΔF = 9.40x105 N
Correct Answer: 4.71x105 N
Why am I double what the answer is suppose to be?